package calculation;

/**
 * Reverse digits of an integer.

 * Example1: x = 123, return 321
 * Example2: x = -123, return -321
 * 
 * Have you thought about this?
 * Here are some good questions to ask before coding. 
 * Bonus points for you if you have already thought through this!
 * 
 * If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.

 * Did you notice that the reversed integer might overflow? 
 * Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. 
 * How should you handle such cases?

 * For the purpose of this problem, 
 * assume that your function returns 0 when the reversed integer overflows.
 *
 */
public class ReverseInteger {
	
	public int reverse(int x) {
        long r = 0;
        while (x != 0) {   
            r = r * 10 + x % 10;
            if (r > Integer.MAX_VALUE || r < Integer.MIN_VALUE) return 0;
            x /= 10;
        }
        return (int) r;
    }

	public static void main(String[] args) {
		// TODO Auto-generated method stub

	}

}
